x^2+2x-147=0

Solution for x^2+2x-147=0 equation:

x^2+2x-147=0

a = 1; b = 2; c = -147;
Δ = b2-4ac
Δ = 22-4·1·(-147)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{37}}{2*1}=\frac{-2-4\sqrt{37}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{37}}{2*1}=\frac{-2+4\sqrt{37}}{2}
$